1.Oblicz zawartość procentową pierwiastków. CaCO3 x 6H2O MgSO4 x 4H2O Z góry dziękuję ; )

__________________________________________________________________ CaCO3 x 6H2O M CaCO3 x 6H2O = 40 + 12 + 3*16 + 6(1*2 + 16) = 40 + 12 + 48 + 108 = 208 u % Ca = 40/208 * 100% = 19 % % C = 12/208 * 100% = 6 % % O = 144/208 * 100% = 69 % % H = 12/208 * 100% = 6 % __________________________________________________________________ MgSO4 x 4H2O M MgSO4 x 4H2O = 24 + 32 + 4*16 + 4(1*2 + 16) = 24 + 32 + 64 + 72 = 192 u % Mg = 24/192 * 100% = 12 % % S = 32/192 * 100% = 17 % % O = 128/192 * 100% = 67 % % H = 8/192 * 100% = 4 % ___________________________________________________________________