hey:) a) 1/2x-3/4[x-(4x+1)]=1-x+1/4 1/2x-3/4(x-4x-1)=1-x+1/4 1/2x-3/4x+3x+3/4x=1-x+1/4 1/2-3/4x+3x+x=1+1/4-3/4 2/4x-3/4x+3x+x=2/4 4i2/4x-3/4x=2/4 18/4x-3/4x=2/4 15/4x=2/4 / * 4/15 x=8/60 x=2/15 b)2/3(3x-1)-2/3[2x+3(x-2)]=1 2x-2/3-2/3(2x+3x-6)=1 2x-2/3-4/3x-2x+4=1 2x-4/3x-2x=1-4+2/3 -4/3 x=1i2/3 - 4 -4/3 x=-2i1/3 /* (- 3/4) x= (- 7/3) * (-3/4) x=1i3/4
A)1/2x - 3/4[x-(4x + 1)]=1 - x + 1/4 |x4 2x - 3[x-(4x + 1)]=4 - 4x + 1 |-1 2x -12x=3 - 4x -10x=3 - 4x |+4x -6x=3 |:(-6) x=-1/2 B)2/3(3x - 1) - 2/3[2x + 3(x - 2)]=1 |x3 2(3x - 1) - 2[2x + 3(x - 2)]=3 |+2 6x - 2 - 10x=5 -4x - 2=5 |+2 -4x=7 |:(-4) x=-1,75 Mam nadzieję ,że dobrze :)
A) 1/2x - 3/4 [x-(4x+1)]=1-x+1/4 ½x-¾[x-4x-1]=1-x+¼ ½x-¾x+3+¾=1-x+¼ ½x-¾x+x=1+¼-3-¾ ¾x=-2,5 x=-3⅓ B) 2/3(3x-1)-2/3[2x+3(x-2)]=1 2x-⅔-⅔[2x+3x-6]=1 2x-⅔-1⅓x-2x+4=1 2x-1⅓x-2x=1+⅔-4 -1⅓x=-2⅓ x=1¾
