a)M(masa) Cl₂= 2 × 35,5g/mol = 71g/mol b)M P₄ = 4 × 31g/mol= 124g/mol c)M KBr = 39g/mol + 80g/mol = 119g/mol d)M H₂S =2 × 1g/mol + 32g/mol= 34g/mol e) NH₃ =14g/mol + 3×1g/mol= 17g/mol f)M Na₂SO₄ = 2× 23g/mol + 32g/mol + 4× 16g/mol= 142g/mol g)M (NH₄)₂CO₃= 4× 14g/mol + 4× 1g/mol +12g/mol + 3× 16g/mol = 120g/mol h)M Mg₃(PO₄)₂ = 3× 24g/mol + 2× 31g/mol + 8× 16g/mol= 262g/mol i)M MgO =24g/mol + 16g/mol= 40g/mol j)M NaF =23g/mol + 19g/mol= 42g/mol k)M CaO = 40g/mol + 16g/mol= 56g/mol l)M H₂SO₄=2× 1g/mol + 32g/mol + 4× 16g/mol= 98g/mol
mCl2= 2*35u=70u mP4=4*31u=124u mKBr=40u+80u=120u mH2S=2*1u+32U=34u mNH3=14u+3*1u=17u mNa2So4=2*23u+32u+4*16u=142u m(NH4)2CO3=(14u+4*1u)*2+12u+3*16u=28u+8u+12u+48u=96u mMg3(PO4)2=3*24u+(31u+4*16u)*2=72u+62u+128u=262u mMgO=24u+16u=40u mNaF=23u+19u=42u mCaO=40u+16u=56u mH2SO4=2*1u+32u+4*16u=98u
Oblicz masy cząsteczkowe podanych substancji. a)Cl2 , b) P4 , c)KBr , d)H2s , e)NH3 , f)Na2SO4 , g) (NH4)2CO3 , h) Mg3(PO4)2 , i)MgO , j)NaF , k)CaO , i)H2SO4 Z Góry dzięki....
