Oblicz procent wagowy pierwiastków w związkach a) NH₃ b) CuSO₄

NH3=14 +3=17 17-100% 14-x N x=82.3 H-17.7 Cuso4=64+32+48-144 144-14000% 64-x x-cu 44.4% 144-100 32-x x S 22.2% O 33.4%

a) NH3 MNH3 = 14u + 3u = 17u MN = 14u MH = 3 * 1U = 3u %N = (14u/17u) * 100% = 82% %H = (3u/17u) * 100% = 18% b) CuSO4 MCuSO4 = 64u + 32u + 4 * 16u = 160u MCu = 64u MS = 32u MO = 4*16u = 64u %Cu = (64u/160u)*100% = 40% %S = (32u/160u) *100% = 20% %O = 100% - 60% = 40%