oblicz masę cząsteczkową: C2H5OH,Ch3COOC7H15,C3H7OH,C5H11COOH

oblicz masę cząsteczkową: C2H5OH,Ch3COOC7H15,C3H7OH,C5H11COOH
Odpowiedź

C2H5OH=2*12u+5*1u+16u+1u=24u+5u+17u=46u CH3COOC7H15=12u+3*1u+12u+16u+16u+7*12u+15*1u=59u+84u+15u=158u C3H7OH=3*12u+7*1u+16u+1u=36u+7u+17=60u C5H11COOH=5*12u+11*1u+12u+16u+16u+1=60u+11u+28u+17u=116u

C2H5OH = 2 * 12u + 5 * 1u + 16u + 1u = 24u + 5u + 17u = 46u CH3COOC7H15 = 12u + 3 * 1u + 12u + 16u + 16u + 7 * 12u + 15 * 1u = 59u + 84u + 15u = 158u C3H7OH = 3 * 12u + 7 * 1u + 16u + 1u = 36u + 7u + 17 = 60u C5H11COOH = 5 * 12u + 11 * 1u + 12u + 16u + 16u + 1 = 60u + 11u + 28u + 17u = 116u

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