Jak rozwiazac takie rownanie(ulamki sa w postaci np. 5/6): 2/3y-5/6(12y-18)+1/12(4y-8)=1/9(3-9)-3

2/3y-10y+15+1/3y-2/3=-2/3-3 1y-10y=-2/3-3-15+2/3 -9y=-18 y=2

2/3y-5/6(12y-18)+1/12(4y-8)=1/9(3-9)-3 2/3y - 10y + 15 + 7/6 - 2/3 = 1/3 - 1 - 3 / *6 4y - 60y + 90 + 7 - 4 = 2 - 6 - 18 4y - 60y = 2 - 6 - 18 - 90 - 7 + 4 -5ry = -117 / : - 54 y = 2 1/6