Ile otrzymamy soli jeśli użyjemy 1kg zasady solowej. Wzór: NaOH+HCl---------NaCl+H2O

NaOH+HCl---------NaCl+H₂O mNaOH = 23u + 16u + 1u = 40u mNaCl = 23u + 35,5u = 58,5u 40u NaOH --- 58,5u NaCl 1 kg NaOH --- x 40x = 58,5 /:40 x = 1,46 kg

1 kg=1000 g mNaOH= 40g mNaCl= 58,5g 1000g NaOH ------------x g NaCl 40g NaOH--------------- 58,5g NaCl x= 1462,5 g =1,4625 g NaCl

NaOH+HCl---NaCl+H₂O m NaOH=23u+16u+1u=40u m NaCl=23u+35,5u=58,5u 40u NaOH---58,5u NaCl 1 kg NaOH---x 40x=58,5/:40 x=1.46 kg