2[x+1]=4 2x + 2 = 4 2x = 2 /:2 x = 1 2[x-1]=4 2x - 2 = 4 2x = 6 /:2 x = 3 3[x-2]=x 3x - 2 = x 2x = 2 /:2 x = 1 3[2x =3]=x-1 ????? zakładam, ze 3[2x - 3] = x - 1 6x - 9 = x -1 5x = 8 /:5 x = 8/5 x= 1 3/5 4[x-1]=3[x+1] 4x - 4 = 3x + 3 x = 7 -[x-1]=2 -x + 1 = 2 -x = 1 /:(-1) x = -1 1-3[x+1]=x 1- 3x +3 = x -2x = 4 /:(-2) x = -2 [x+1]-[x-1]=1 x² -x + x -1 = 1 x² = 2 x = pierwiastek z 2 1/2[x-1]=4 1/2x - 1/2 = 4 /*2 x -1 =8 x = 9 -1/4[2-x]=3/4x -1/2 + 1/4x = 3/4 x /*4 -2 + x = 3x -2x = 2 /:(-2) x = -1 -2[x+1/2]-3[x+1/3]=0 -2x -1 -3x -1 = 0 -5x = 2 /:(-5) x = - 2/5
2[x+1]=4 2x + 2 =4 / -2 2x = 2 / :2 x = 1 2[x-1]=4 2x - 2 = 4 / +2 2x = 6 / :2 x = 3 3[x-2]=x 3x - 6 = x / -3x -6=-2x / * (-1) 2x = 6 / : 2 x = 3 3[2x=3]=x-1 zakładam że + 6x + 9 = x - 1 / - x 5x + 9 = -1 / - 9 5x = - 10 / : 5 x = -2 4[x-1]=3[x+1] 4x - 4 = 3x + 3 / +4 4x = 3x + 7 / -3x x = 7 -[x-1]=2 -x + 1 = 2 / -1 -x = 1 / * (-1) x = -1 [x+1]-[x-1]=1 x + 1 - x + 1 = 1 2 = 1 - równanie nieprawidłowe, nie jestem pewna nazwy i wyniku ( takie rozwiązania tez są możliwe ;)) 1/2[x-1]=4 1,5 x - 0,5 = 4 / *2 3x - 1 = 8 / +1 3x = 9 / :3 x = 3 -1/4[2=x]=3/4x (stawiam że będzie dodawanie) -1/2 + 1/4x = 3/4 x /*4 -2 + x = 3x / - x -2 = 2x / :2 x = 1 -2[x+1/2]-3[x+1/3]=0 -2x -1 - 3x - 1 = 0 -5x - 2 = 0 / +2 -5x = 2 / : (-5) x = 0,4
