1) (4x-5)/(x+3) = 4x 2) x²>16 3) x²+5x ≤ 0

(4x-5)/(x+3)=4x /*(x+3) 4x-5=4x²+12x 4x²-12x+4x-5=0 4x²-8x-5=0 Δ=b²-4ac Δ=(-8)²-4*4*(-5) Δ=64+80 Δ=144 √Δ=12 x₁=-b-√Δ/2a x₁=8-12/2*4 x₁=-4/8 x₁=-½ x₂=-b+√Δ/2a x₂=8+12/2*4 x₂=20/8=2½ x²>16 x²-16>0 (x-4)(x+4)>0 x≠4 v x≠-4 x²+5x≤0 Δ=5²-4*1*0 Δ=25 √Δ=5 x₁=-5-5/2*(1)=-10/2 x₁=-5 x₂=-5+5/2 x₂=0