Obicz procentowa zawartosc pierwiastkow w PROPANONIE. (keton) Krok po kroku ;]

mCH3COCH3 =3*12u + 6*1u + 1*16u = 36u + 6u + 16u = 58u mC = 36u 58u - 100% 36u - x x = 36u*100%/58u = 62,06%C mH = 6u 58u - 100% 6u - x x = 6u*100%/58u = 10,34%H mO = 16u 58u - 100% 16u - x x = 16u*100%/58u =27,58%O