a) 1/2x - 3/4[x-(4x+1)]=1- x+1/4 1/2x - 3/4 [x-4x-1] = 1-x + 1/4 1/2x - 3/4x + 3x + 3/4 = -x +5/4 3 i 3/4x = 1/2 x= 2/15 b) 2/3(3x-1)-3/2[2x+3(x-2)]=1 2x-2/3-3x-9/2x+9=1 -x-9/2x=-8+2/3 x=25/12=2 i 1/12
a) 1/2x - 3/4[x-(4x+1)]=1- x+1/4 1/2x - 3/4[x-4x-1]=1-x+1/4 1/2x - 3/4x - 3x- 3/4=1-x+1/4 /*4 2x-3x-12x-3=4-4x+1 2x-3x-12x+4x=1+3 -9x=4 /:(-9) x= -4/9 b) 2/3(3x-1)-3/2[2x+3(x-2)]=1 2x-2/3-3/2[2x+3x-6]=1 2x-2/3-3x-4,5 x+9=1 -2/3+9-1=-2x+3x+4,5x -2/3+27/3-1=5,5x 25/3-1=5,5x 8 i 1/3-1=5,5x 7 i 1/3=5,5x / :5,5 x=1 i 1/3 Na pewno dobrze:)
a) 1/2x-3/4[x-[4x+1]]=1-x+1/4 1/2x-3/4[-3x+1-x]=1-x+1/4/*4 2x-3[-3+1-x]=4-4x+1 2x+6-3+x=4-4x-1 2x+x+4x=-6+3+4-1 7x=0 brak rozwiazania rownania b) 2/3[3x-1]-3/2[2x+3[x-2]]=1/*6 4[3x-1]-9x[2x+3[1-2]]=6 12x-4-9x[2x+3-6]=6 12x-4-18x-27x+54=6 12x-18x-27x=4-54+6 21x=-44//21 x=-2i2/21