rozwiąż -ile wynoszą b,c,d,e,f 4b+3=3b-4 7+3c=-5+2c 5d+2=3d 6e-2=7e+5 6f-1=f+2

4b+3=3b-4 4b-3b=-4-3 b=-7 7+3c=-5+2c 3c-2c=-5-7 c=-12 5d+2=3d 5d-3d=-2 2d=-2 d=-1 6e-2=7e+5 6e-7e=5+2 -e=7 e=-7 6f-1=f+2 6f-f=1+2 5f=3 F=3/5  trzy piąte liczę na naj;**

4b + 3 = 3b - 4 4b - 3b = -4 - 3 b = -7 7 + 3c = -5 + 2c 7 + 5 = 2c - 3c 12 = -c -12 = c 5d + 2 = 3d 5d - 3d = -2 2d = - 2 | :2 d = -1 6e - 2 = 7e + 5 -2 - 5 = 7e - 6e -7 = e 6f - 1= f + 2 6f - f = 2 + 1 5f = 3 | :5 f = 35