zapisz w postaci jednej potęgi a następnie oblicz a. (-2)²×(-2)³ __________ (-2)⁵ b. 125²÷(√5)⁴ _________ ( ⅕)⁻² c. [(1⅗)⁴]⁻½

a. (-2)²×(-2)³ (-2)²⁺³ (-2)⁵ __________= ___________ = _________ = (-2)⁵ :(-2)⁵ = (-2)⁰ = 1 (-2)⁵ (-2)⁵ (-2)⁵ b. 125²÷(√5)⁴ (5³)² : (5 ¹/²)⁴ 5⁶ : 5² 5⁶⁻² _________ = ______________ = ______ = ____ = 5⁴ :5² = 5⁴⁻² = 5²= 25 ( ⅕)⁻² 5² 5² 5² c. [(1⅗)⁴]⁻½ = [(8/5)⁴]⁻¹/² = 8/5⁻² = 5/8² = 25/64