Rozwiąż równanie: 3(y+2)=5 (y+3)=5y+2+2y 1/2y + 1/3= 7/6

3y+6=5 | -6 3y= -1 | :3 y =0,33 (y+3)=5y+2+2y |-3 y=7y -1 | -7y -6y=-1 |: (-6) y=0,16 1/2y+1/3=7/6 1/2y+2/6=7/6 | - 2/6 1/2y=5/6 | : 1/2 y=1 4/6

3(y+2)=5 3y+6=5 3y=-1 y=-1/3 (y+3)=5y+2+2y 6y=1 y=1/6 1/2y+1/3=7/6 1/2y=5/6 y=10/6 y=1 2/3

1) 3(y+2)=5 3y+6=5 3y=5-6 3y=-1 |:3 to już sobie dolicz :p 2) (y+3)=5y+2+2y y+3=5y+2+2y y-5y-2y=2-3 -6y=-1 |:(-6) to też policz ;p 1/2y+1/3=7/6 1/2y=7/6-1/3 1/2y=7/6-2/6 1/2y=5/6