[2²-√2¼×(-1⅓)²]÷(-⅓)³

[2²-√2¼×(-1⅓)²]÷(-⅓)³= [4-√9/4×(-4/3)²]÷(-1/27)= [4-3/2×16/9]*(-27)= [5/2×16/9]*(-27)= [5×8/9]*(-27)= [40/9]*(-27)= [40]*(-3)=-120

13+4√2 ______ ÷1/27≈168 3

[2²-√2¼×(-1⅓)²]÷(-⅓)³ [4-pierwiastek z 9/4x (-4/3) do potęgi 2] +(-1/27) [4-3/2x*16/9]+(-1/27) [4-8/3]+(-1/27) 3 i 5/3 -1/27 3 i 45/27-1/27 3i44/27