prosze dokladne obliczenia log₃x=9 oblicz x x-5/x+3 = 2/3 x+3/(5-x)(x+2)=0

log₃x=9 oblicz x 3⁹ = x x = 19683 x-5/x+3 = 2/3 x-5 = ⅔(x+3) x-5 = ⅔x + 2 x - ⅔x = 2+5 ⅓x = 7 x = 21 x+3/(5-x)(x+2)=0 x+3=0 x = -3

log₃x=9 3 do potęgi 9=x x=19683 x-5/x+3 = 2/3 3(x-5)=2(x+3) 3x-15=2x+6 x=21 x+3/(5-x)(x+2)=0 x+3=0 x= -3