Pomóżcie :) Jak to rozwiązac nie bardzo wiem ;D 3,6:(-4/9)+(-1,9)= ??? Jeszcze to: 3/2x7+1/2 do potęgi 2 :3/2 do potegi 2) x [3/5 - (2 2/5 ) ] = ???

/ - kreska ułamkowa 3,6:(-4/9)+(-1,9)= (36/10) /(-4/9)-1,9 = 36/10*(-9/4)-1,9 = -81/10-1,9 = -8,1-1,9 = -10 3/2x7+1/2 do potęgi 2 :3/2 do potegi 2) x [3/5 - (2 2/5 ) ] 3/2*7+(1/2)²/(3/2)²*[3/5-(2 2/5)] = 21/2+(1/4)/(9/4)*(3/5-12/5) = 21/2+1/4*4/9*(-9/5) = 21/2+1/9*(-9/5) = 21/2+(-1/5) = 21/2-1/5 = 105/10-2/10 = 103/10 = 10 3/10 = 10,3