oblicz masę molową: a. NaHCO₃ b. Fe₂O₃ c. Na₂SO₄
oblicz masę molową:
a. NaHCO₃
b. Fe₂O₃
c. Na₂SO₄
Odpowiedź
mNaHCO₃ = 23g/mol + 1g/mol + 12g/mol + 48g/mol = 84g/mol mFe₂O₃ = 2*56g/mol + 3*16g/mol = 160g/mol mNa₂SO₄ = 2*23g/mol + 32g/mol + 64g/mol = 142g/mol
mNaHCO₃ = 23g/mol + 1g/mol + 12g/mol + 48g/mol = 84g/mol mFe₂O₃ = 2*56g/mol + 3*16g/mol = 160g/mol mNa₂SO₄ = 2*23g/mol + 32g/mol + 64g/mol = 142g/mol
m NaHCO3=23g/mol + 1g/mol + 12g/mol + 48g/mol = 84g/mol m Fe2O3=2*56g/mol + 3*16g/mol = 160g/mol m Na2SO4=2*23g/mol + 32g/mol + 64g/mol = 142g/mol
Dodaj swoją odpowiedź