8-3x-2[4-(x+5)]=3(x+1)-1 rozwiaz rownanie napisz sprawdzenie do teo rownania

8-3x-2[4-(x+5)]=3(x+1)-1 8-3x-2[4-x-5]=3x+3-1 8-3x-8+2x+10=3x+3-1 -3x+2x-3x=3-1-8+8-10 -4x=-8 : (-4) x=2

8-3x-2[4-(x+5)]=3(x+1)-1 8 - 3x - 2 ( 4 - x - 5 ) = 3x + 3- 1 8 - 3x - 8 + 2x + 10 = 3x + 3 - 1 - 3x + 2x - 3x = -1 + 3 - 8 + 8 - 10 - 4x = - 8 / : ( -4) x = 2 spr: L= 8 - 3 * 2 - 2 [ 4 - ( 2 + 5 ) ] = 8 - 6 - 2 ( 4 - 2 - 5 ) = 2 - 8 + 4 + 10 = 8 P= 3 ( 2 + 1 ) - 1 = 3 * 3 - 1 = 9 - 1 = 8 L= P

8-3x-2[4-(x+5)]=3(x+1)-1 8-3x-2{4-x-5]=3x+3-1 8-3x-8+2x+10=3x+2 -x+10=3x+2 -3x-x=2-10 -4x=-8 / :(-4) x=2 spr. L= 8-3*2-2[4-(2+5)] = 8-6-2[4-2-5]=2-8+4+10=8 P= 3(2+1)-1=6+3-1= 8 L=P :*