(1/2x+1)+[1/2(1/2x-1)+1]+[1/2(1/2(1/2x-1)-1)+3]=x

(1/2x+1)+[1/2(1/2x-1)+1]+[1/2(1/2(1/2x-1)-1)+3]=x 1/2+1+[1/4x-1/2+1]+[1/2(1/4x-1/2-1)+3]=x 1/2+1+1/4x+1/2+[1/8x-1/4-1/2+3]=x 1/2+1+1/4x+1/2+1/8x-1/4-1/2+3=x 1/4x+1/8x-x=-1/2-1-1/2+1/4+1/2-3 2/8x+1/8x-x=-1-1/2+1/4-3 5/8x=-1-2/4+1/4-3 5/8x=-2 1/4 5/8x=9/4 /*8/5 x=18/5 x=3 3/5

(1/2x+1)+[1/2(1/2x-1)+1]+[1/2(1/2(1/2x-1)-1)+3]=x 1/2+1+[1/4x-1/2+1]+[1/2(1/4x-1/2-1)+3]=x 1/2+1+1/4x+1/2+[1/8x-1/4-1/2+3]=x 1/2+1+1/4x+1/2+1/8x-1/4-1/2+3=x 1/4x+1/8x-x=-1/2-1-1/2+1/4+1/2-3 2/8x+1/8x-x=-1-1/2+1/4-3 5/8x=-1-2/4+1/4-3 5/8x=-2 1/4 5/8x=9/4 /*8/5 x=18/5 x=3 3/5 O Boshe ile liczenia..masakra..

(1/2x+1)+[1/2(1/2x-1)+1]+[1/2(1/2(1/2x-1)-1)+3]=x 1/2+1+[1/4x-1/2+1]+[1/2(1/4x-1/2-1)+3]=x 1/2+1+1/4x+1/2+[1/8x-1/4-1/2+3]=x 1/2+1+1/4x+1/2+1/8x-1/4-1/2+3=x 1/4x+1/8x-x=-1/2-1-1/2+1/4+1/2-3 2/8x+1/8x-x=-1-1/2+1/4-3 5/8x=-1-2/4+1/4-3 5/8x=-2 1/4 5/8x=9/4 /*8/5 x=18/5 x=3 3/5 sory bo zle obliczyłam wtedy zamaist 8 napsiałam 7 i inny winik wyszedł