Proszę o całkowite rozwiązanie, z wszystkimi obliczeniami itp. :) 1. x+1= 2(3x-1) 2. 3x- (2x +3)= 5x 3. 5-2( 3-x)= x-1 4. 2x-1 ≤ x-5 5. 2(x+3)-1 > x-5 6. 3(x-1)-2(2+x) > 1-x DAJĘ NAJ!!!

1. x+1= 2(3x-1) x + 1 = 6x - 2 x - 6x = -2 - 1 -5x = -3 x = 3/5 2. 3x- (2x +3)= 5x 3x - 2x - 3 = 5x x - 5x = 3 -4x = 3 x = -3/4 3. 5-2( 3-x)= x-1 5 - 6 + 2x = x - 1 2x - x = -1 + 6 - 5 x = 0 4. 2x-1 ≤ x-5 2x - x ≤ -5 + 1 x ≤ -4 5. 2(x+3)-1 > x-5 2x + 6 - 1 > x - 5 2x - x > -5 - 5 x > -10 6. 3(x-1)-2(2+x) > 1-x 3x - 3 - 4 - 2x > 1 - x x + x > 1 + 7 2x > 8 x > 4

1) x+1=2(3x-1)                      2)3x-(2x+3)=5x                       3)5-2(3-x)=x-1        x+1=6x-2/-6x-1                     3x-2x-3=5x                            5-6+2x=x-1      -5x=-3                                   x-3=5x/-5x+3                        -1+2x=x-1/+1-x       x=3/5                                    -4x=3                                        x=0                                                   x=-3/4      4)2x-1 ≤x-5/-x+1                    5)2(x+3)-1 >x-5                       6) 3(x-1)-2(2+x)>1-x      x ≤-4                                     2x+6-1 >x-5/-x-5                      3x-3-4-2x>1-x                                                   x >-10                                      x-7>1-x/+x+7                                                                                                    2x>8                                                                                                    x>4