zadanie 1 rozwiąż nierówność (2x-1)(2x+2)-(4x+5)²=-4x-2 4x² + 2x - 2 -(16x² + 40x + 25) = -4x -2 4x² + 2x - 2 -16x² - 40x - 25 = -4x -2 -12x² -38x - 27 = -4x -2 -12x² -34x - 25 = 0 Δ = 1156 - 4 * (-12) * (-25) = 1156 - 1200 = 44 Δ= √44 x = - (34 + √44/ 24) x = -(34 - √44/24) 4*(4x-2/3)-2<6-5x/3 16x - 8/ 3 - 2 < 6-5x/3 21x - 14 / 3 - 2 < 0 /*3 21x - 14 - 6 < 0 21x - 20 < 0 21x < 20/:21 x < 20/21
(2x-1)(2x+2)-(4x+5)²=-4x-2 4x² + 2x - 2 -(16x² + 40x + 25) = -4x -2 4x² + 2x - 2 -16x² - 40x - 25 +4x+2= 0 -12x² -38x - 27+4x+2 =0 -12x² -34x - 25 = 0 delta = 1156 - 4*(-12)*(-25) = 1156 - 1200 = 44 delta= √44 x1 = - (34 + √44/ 24) x2 = -(34 - √44/24) 4*(4x-2/3)-2<6-5x /3 16x - 8/ 3 - 2 < 6-5x /3 21x - 14 / 3 - 2 < 0 /*3 21x - 14 - 6 < 0 21x - 20 < 0 21x < 20 x < 20/21
