Oblicz pole całkowite i objestość stożka o tworzącej 6 i stopniu 45

Dane: l = 6 α = 45 V = ? P = ? P = πr² + πrl V = 1/3πr²h r/h = tg(α/2) r = h*tg(α/2) h² + r² = l² h² + [h*tg(α/2)]² = l² h² + h²tg²(α/2) = l² h²[ 1 + tg²(α/2)] = l² /: [ 1 + tg²(α/2)] h² = l²/[ 1 + tg²(α/2)] h = l/√([ 1 + tg²(α/2)]) h = 6/√([ 1 + tg²22,5]) h = 6/ √(1 + tg²22,5) h = 6/√(1 + 0,4²) h = √1,16 h =1,1 r = h*tg(α/2) r = 1,1* 0,4 r = 0,44 P = πr² + πrl P = π(0,1936 + 0,44*6) P = 2,8π V = 1/3πr²h V = 1/3π(0,44)²*1,1 V = 0,8π