oblicz ∛1⁹¹/₁₂₅= (-4)×(-4)×3×3×(-4)= (-2)×½×(-2)×½= 2×∛8+3×√4= √¼+(-½)² wstaw właściwy znak <,=,>. 3×2³ ...... 4×3² 6-3⁰ ......2×2² (-3)⁴ ......3⁴ (-2²)×9...... 9¹×2² 4⁰×4³....... 5⁰×4³ (-2)³×√2500.......(-2)²×√0,25

Zad. 1) a) ∛1⁹¹/₁₂₅ = ∛216/125 = 6/5 = 1,2 b) (-4)×(-4)×3×3×(-4 )= 16 * (-4)*9 = - 64*9 = -576 c) (-2)×½×(-2)×½ = (-1)*(-1) = 1 d) 2×∛8+3×√4 = 2*2 + 3*2 = 4 + 6 = 10 e) √¼ + (-½)² = 0,5 + 0,25 = 0,75 Zad. 2) a) 3×2³ < 4×3² b) 6-3⁰ < 2×2² c) (-3)⁴ = 3⁴ d) (-2²)×9 = 9¹×2² e) 4⁰×4³ = 5⁰×4³ f) (-2)³×√2500 < (-2)²×√0,25