Proszę o napisanie spalania całkowitego i niecałkowitego podanych alkanów : metan etan propan butan pentan heksan heptan oktan nonan dekan z dobraniem współczynników ! DAJE NAJJ!

metan CH4+2O2-->CO2+2H2O CH4+O2-->C+2H2O etan 2C2H6+7O2-->4CO2+6H2O 2C2H6+3O2-->4C+6H2O propan C3H8+5O2-->3CO2+4H2O C3H8+2O2-->3C+4H2O butan 2C4H10+13O2-->8CO2+10H2O 2C4H10+5O2-->C+10H2O pentan C5H12+8O2-->5CO2+6H2O C5H12+3O2-->5C+6H2O heksan 2C6H14+19O2-->12CO2+14H2O 2C6H14+7O2-->12C+14H2O heptan C7H16+11O2-->7CO2+8H2O C7H16+4O2-->C+8H2O oktan 2C8H18+25O2-->16CO2+18H2O 2C8H18+9O2-->16C+18H2O nonan C9H20+14O2--->9CO2+10H2O C9H20+5O2-->9C+10H2O dekan 2C10H22+21O2-->20CO2+22H2O 2C10H22+11O2-->20C+22H2O no to chyba tyle prosze bardzo

metan: CH4+2O2->CO2+2H2O (spalanie całkowite) CH4+O2->C+2H2O (spalanie niecałkowite) etan: 2C2H6+7O2->4CO2+6H2O (spalanie całkowite) 2C2H6+3O2->4C+6H2O (spalanie niecałkowite) propan: C3H8+5O2->3CO2+4H2O (spalanie całkowite) C3H8+2O2->3C+4H2O (spalanie niecałkowite) butan: 2C4H10+13O2->8CO2+10H2O (spalanie całkowite) 2C4H10+5O2->C+10H2O (spalanie niecałkowite) pentan: C5H12+8O2->5CO2+6H2O (spalanie całkowite) C5H12+3O2->5C+6H2O (spalanie niecałkowite) heksan: 2C6H14+19O2->12CO2+14H2O (spalanie całkowite) 2C6H14+7O2->12C+14H2O (spalanie niecałkowite) heptan: C7H16+11O2->7CO2+8H2O (spalanie całkowite) C7H16+4O2->C+8H2O (spalanie niecałkowite) oktan: 2C8H18+25O2->16CO2+18H2O (spalanie całkowite) 2C8H18+9O2->16C+18H2O (spalanie niecałkowite) nonan: C9H20+14O2->9CO2+10H2O (spalanie całkowite) C9H20+5O2->9C+10H2O (spalanie niecałkowite) dekan : 2C10H22+21O2->20CO2+22H2O (spalanie całkowite) 2C10H22+11O2->20C+22H2O (spalanie niecałkowite)