Rozwiąż nierówność 2x²-2x-24<0 6x≥5x² -6x²-5x=4=0 x²-5x>-6

a) 2x²-2x-24<0 Δ=b²-4ac=(-2)²-4*2*(-24)=4+96=100 √Δ=10 x₁=-b+√Δ/2a=2+10/4=12/4=3 x₂=-b-√Δ/2a=2-10/4=8/4=2 b)6x≥5x² -5x²+6x≥0 x(-5x+6)≥0 x=0 -5x+6=0 -5x=-6 x=1⅕ c)-6x²-5x+4=0 Δ=(-5)²-4*(-6)*4=25+96=121 √Δ=11 x₁=5+11/-12=16/-12=1¾ x₂=5-11/-12=-6/-12=½ d)x²-5x>-6 x²-5x+6>0 Δ=(-5)²-4*1*6=25-24=1 √Δ=1 x₁=5+1/2=6/2=3 x₂=5-1/2=4/2=2 :))

1. 2x^-2x-24< 0 (^-kwadrat) delta =(-2)^- 4*2*(-24) = 196 Vd =V196 =14 X1 =(2-14)/4 = -3 X2 =(2 +14)/4 = 4 Odp. X<4 2. 6x>=5x^ 6x-5x^>= 0 x(6-5x)>= 0 X1 = 0,lub 6-5x>= 0 -5x>= -6/(-5) x<= 6/5 x<=1 1/5 Odp. 1 1/5=>X>=0 3. -6x^-5 =4= 0 ? 4. x^-5x> -6 x^-5x +6>0 delta = 25-24=1 X1 =(5-1)/2 =2 X2 =(5+1)/2 =3 Odp.X>2