Oblicz zawartość procentową (procent masowy ) metali w solach AlCL₃ Pb(NO₃)₂ Na₂SO₄

AlCl3 mAl=27g mCl= 35,5g mAlCl3= 27g+3*35,5g=133,5g 27g/133,5g*100%= 20,23% Pb(NO3)2 mPb(NO3)2= 207g+2*14g+6*16g= 331g 207/331*100%= 62,54% Na2SO4 mNa2SO4= 2* 23g+32g+4*16g= 142g 46/142*100%=32,4%

alClз 27u+3*35u=132u 132u---100% 27u----x x=27*100/132=20,45% Pb(NO₃)₂ 207u+2*14u+6*16u=331u 331u====100% 207u====x x=207*100/331=62,54% Na₂SO₄ 2*23u+32u+4*16=142u 142u====100% 46u====x x=46*100/142=32,40%

AlCl3 M AlCl3 = 132u %Al = M Al / M AlCl3 *100% %Al = 2700/132 = 20,5 % Pb(NO3)2 M Pb(NO3)2 = 331u % Pb = M Pb / M Pb(NO3)2 * 100 % % Pb = 20700/ 331 = 62,5 % Na2SO4 M Na2SO4 = 142 u % Na = M Na / M Na2SO4 * 100% % Na = 4600/ 142 = 32,4 %