2x(kwadrat) -3x+1=0 oblicz delte, x1,x2

2x^2-3x+1=0 delta= 9-8=1 x1=(3-1)/4= 1/2 x2=(3+1)/4=1

Delta = b^2 -4ac= (-3)^2 - 4*2*1 = 9 - 8 =1 Pierw. z delty to 1. x1 = -b-pierw. z delty / 2 = -(-3) - 1 / 4= 2/4 = 1/2 x2 = -b- +pierw. z delty / 2 = -(-3) +1/4= 4/4=1

2x^{2}-3x+1 = 0 a=2 b=-3 c=1 delta = b^{2}-4ac delta = (-3)^{2}-4*2*1 delta = 9-8 delta = 1 pierw. z delty = 1 x1 = (-b-pierw. z delty)/2a x1 = (3-1)/4 = 1/2 x2 = (-b+pierw. z delty)/2a x2 = (3+1)/4 = 1