Oblicz pojemność baterii kondensatorów, przedstawionych na rysunku: C1 = 1F C2 = 2F C3 = ⅓ F C4 = 1F

1/C₁₂=1/C₁+1/C₂ 1/C₁₂=1+½ 1/C₁₂=3/2 C₁₂=⅔F C=C₁₂+C₃ C=⅔F+⅓F C=1F 2. C₁₂=C₁+C₂ C₁₂=3F 1/C₁₂₃=1/C₁₂+1/C₃ 1/C₁₂₃=⅓+1/⅓ 1/C₁₂₃=10/3 C₁₂₃=3/10F C=C₁₂₃+C₄ C=0,3F+1F C=1,3F