oblicz f(-2), f(0), f(10) jeśli: reszta zadania na fotce!!!

10a) f(-2)=(-2)²+1=5 f(0)=0²-1=-1 f(10)=10²-1=99 b) f(-2)=(3+2):2=2,5 f(0)=0²+21=21 f(10)=10²+21=121 c) f(-2)=-2×(-2)²=-8 f(0)=0 f(10)=3×10²=300