Określ granice funkcji lim (przy x dążącym 0) sin²x/1-cosx

lim_x->0 sin²x/1-cosx = lim_x->0 (1-cos²x)/(1-cosx) = lim_x->0 (1-cosx)(1+cosx)/(1-cosx) = lim_x->0 (1+cosx) = 1+1 = 2

lim x--> 0 [ sin²x /(1 - cos x)] = lim x-->0 [(1 -cos²x)/(1 - cos x)] = = lim x --> 0 [ ((1 -cos x)*(1 + cos x))/(1 - cos x)] = = lim x --> 0 [1 + cos x ] = 1 + 1 = 2