oblicz mase NH3 K20 NaoH

NH3 N=14u H=1u m NH3=14u + 3*1u = 14u + 3u= 17u     K2O K=39u O=16u m K2O= 2*39u + 16u= 78u + 16u= 94u   NaOh Na=23u O=16u H=1u m NaOH= 23u + 16u + 1u= 40u

mNH3=14u+3*1u=17u mK2O=2*39u+16u=94u mNaOH=23u+16u+1u=40u

masa NH₃ mN= 14g mH= 1g mNH₃= 14g+ 3*1g= 14g+ 3g= 17g   masa K₂O mK= 39g mO=16g mK₂O=  2*39g+ 16g= 78g+ 16g= 94g   masa NaOH mNa=23g mO=16g mH=1g m NaOH= 23g+ 16g+ 1g= 40g 1g=1u Pozdrawiam, kate66 ;)