oblicz pierwszy wyraz i iloraz ciagu geometrycznego (an) wiedzac ze a2=6/7  (szesc siodmych) oraz a3=9/7 

odp w zal

a2 =6/7 a3 =9/7 a1 =?   q = a3/a2 =9/7: 6/7 =9/7 x 7/6 q =3/2 a1 =a2:q a1 =6/7 :3/2 =6/7 x 2/3 a1 = 4/7 =========  

a2 =6/7 a3 =9/7   q = a3/a2 =9/7: 6/7 =9/7* 7/6= 9/6= 3/2 a1 =a2:q=6/7 :3/2 =6/7* 2/3= 12/21= 4/7   odp:a1=4/7 q=3/2