ZAMIEŃ :                                  PILNE !!!!!!!!!!!!!!!!!!!!   a) 15 m/sek²                       zamienić na km/ min²   b) 130 kg/m sześćiennych     zamienić na g/ cm sześćiennych      wyznacz V2:           d t= ---------       V1² - V2²

a) [latex]15 frac{m}{sec^2} = frac {15}{1000} frac{km}{sec^2} = frac{15*60^2}{1000} frac{km}{min^2} = frac{54000}{1000} frac{km}{min^2} = 54 frac{km}{min^2} [/latex] b) [latex] 130 frac{kg}{m^3} = 130*1000 frac{g}{m^3} = 130000 * 100^3 frac{g}{cm^3} = 130 000 000 000 frac{g}{cm^3} [/latex] c) [latex]t = frac{d}{sqrt{V_1^2 - V_2^2}} [/latex]   [latex]t * sqrt{V_1^2 - V_2^2} = d [/latex]   [latex]sqrt{V_1^2 - V_2^2} = frac{d}{t} [/latex]   [potęgowanie obu stron]   [latex]V_1^2 - V_2^2 = (frac{d}{t})^2 [/latex]   [latex]-V_2^2 = (frac{d}{t})^2 - V_1^2 [/latex]   [latex]V_2^2 = V_1^2 - (frac{d}{t})^2 [/latex]   [latex]V_2 = sqrt{V_1^2 -(frac{d}{t})^2 } [/latex]   Pozdrawiam