Oblicz masę cząsteczkową :   NH3, H4P2O7, (NH4)2CO3   Bardzo proszę o pomoc !

Mcz (masa cząsteczkowa ) NH₃ = Mcz N + 3× Mcz H = 14u + 3× 1u= 17u   Mcz H₄P₂O₇ =4 × Mcz H + 2× Mcz P + 7× Mcz O = 4 × 1u + 2× 31u + 7 × 16u= 178u   Mcz (NH₄)₂CO₃ =2 × M cz N + 8 × Mcz H + Mcz C + 3× Mcz O = 2 × 14u + 8 × 1u + 12u + 3× 16u= 96u

NH3=14+3=17u H4P2O7=4+62+112=178u (NH4)2CO3=(14+4)2+12+48=28+8+12+48=96u