Rozpuszczono 2g potasu w 20 g H20. Oblicz Cp i Cm gdy d=1.1 g/cm3   2K+2H20 ----> 2KOH + H2 (utlenia sie)   Oblicz cp i cm

mNa=23u mNaOH=40u Na + H₂O---->NaOH + ½H₂ 23g Na-------40g NaOH 2g Na--------xg NaOH x = 3,48g NaOH   23g Na------1g H₂ 2g Na--------xg H₂ x = 0,09g H₂   mr = 2gNa + 20g H₂O - 0,09g H₂ mr = 21,91g roztworu   Cp=ms*100%/mr Cp=2*100/21,91 Cp = 9,13%   Cm= Cp*d/100%*M Cp=9,13% d=1,1g/cm3=1100g/dm3 M=40g/mol Cm=? Cm = 9,13*1100/100*40 Cm = 2,5moldm3