(4x-2)-(5x+3) = (4x+2)+(-5x-3)= 4xdo 2 potęgi +x+1  dla x= jedna dróga

(4x-2)-(5x+3) =4x - 2 - 5x - 3 = -x - 5 = -(x + 5)   (4x+2)+(-5x-3)= 4x + 2 - 5x - 3 = -x - 1 = -(x + 1)   4xdo 2 potęgi +x+1  dla x= jedna dróga 4 * (½)² + ½ + 1 = 4*¼ + ½ + 1 = 1 + ½ + 1 = 2½

(4x-2)-(5x+3) =4x - 2 - 5x - 3 = -x - 5 = -(x + 5)   (4x+2)+(-5x-3)= 4x + 2 - 5x - 3 = -x - 1 = -(x + 1)   4xdo 2 potęgi +x+1  dla x= jedna druga 4 * (1/2)² + 1/2+ 1 = 4*1/4 + 1/2 + 1 = 1 + 1/2 + 1 = 2