Zapisz w postaci sumy algebraicznej:   d)(2x - 2)²(x + 2) =   Zapisz w jak najprostrzej postaci:   a) (x +1)(x - 2) + (x+2)(x-1) = e) 2(3a² - 1) - (a + 2)(a + 2) =   Z góry dzięki ;) Pelno obliczenia.

(2x-2)²(x+2)= (2x-2)(2x-2)(x+2)= (4x²-4x-4x+4)(x+2)= (4x²-8x+4)(x+2)= 4x³+8x²-8x²-16x+4x+8= 4x³-12x+8   (x+1)(x-2)+(x+2)(x-1)= x²-2x+1x-2+(x²-1x+2x-2)= x²-2x+1x-2+x²-1x+2x-2= 2x²-4     2(3a²-1)-(a+2)(a+2)= 6a²-2-(a²+2a+2a+4)= 6a²-2-a²-2a-2a-4= 5a²-6-4a= 5a²-4a-6