Jaką ilość CaO rozpuści 300 g 15%-go octu?

Z def. stęż. procent. 15g kwasu-----100g roztworu xg kwasu-------300g roztworu x = 45g kwasu   mCaO=56u mCH3COOH=60u CaO + 2CH3COOH---->(CH3COO)2 + H2O 56g CaO-------120g CH3COOH xg CaO---------45g CH3COOH x = 21g CaO

CaO + 2CH3COOH ------> (CH3COO)2Ca + H2O   Cp=ms/mr x 100% 0,15=ms/300 ms=45g CH3COOH   56g CaO ---- 120g CH3COOH X --- 45g CH3COOH X=21g CaO się rozpusci