200 cm3 roztworu zawiera 0,05 mola KOH. Oblicz pH. Bardzo proszę opisać jak to sie robi!

V = 200cm3 = 0.2 dm3 n = 0.05mola KOH   Cm = n/V Cm = 0.05 / 0.2 Cm = 0.25 mol/dm3   [latex]KOH -> K^+ + OH^-[/latex]   pOH = -log[OH-] pOH = -log[0.25] pOH = 0.60   14 = pH + pOH pH = 14 - pOH pH = 14 - 0.60 pH = 13.40