oblicz mase cząsteczkową nastepujacych substancji a)NH3, AL2O3, CA(OH)2 b)CO2, P2O5, NAOH c) SO3, H2S, AL(OH)3 d)H2CO3, H3PO4, HNO3

a) mNH3 =  14u+3x1u= 17u mAl2O3 = 102 u mCa(OH)2= 74u b) mCO2= 44u mP2O5= 142u mNaOH= 40u c) mSO3= 60u mH2S= 34u mAl(OH)3= 78u d) mH2CO3= 62u mH3PO4= 98u mHNO3= 63u  

NH3=14u+1u*3=17u Al2O3=27u*2+16u*3=102u Ca(OH)2=40u+2*16u+2*1u=74u CO2=12u+16u*2=44u P2O5=2*31u+5*16u=142u NaOH=23u+16u+1u=40u SO3=32u+16u*3=80u H2S=1u*2+32u=34u Al(OH)3=27u+3*16u+3*1u=78u H2CO3=2*1u+12u+16*3=62u H3PO4=3*1u+31u+4*16u=98u HNO3=1u+14u+16*3=62u