Proszę o rozwiązanie 2 zadań z załącznika. Pilneee. DAJE NAJJJ:)

Heksan C6H14   CH3-CH-CH2-CH2-CH3 CH 3 DO 2   2-METYLOPENTAN   Pent 1-yn C5H8   CH3-CH2-C = - C-CH3   Pent-3-yn     2,3-DIMETYLOHEPT-3-EN  C9H19 CH3 DO 3 CH3-CH-C-CH=CH2-CH2-CH3 CH3 DO 3 3,3-DIMETYLOHEPT-4-EN   Paradichlorbenzen   Cl<-> Cl Metadichlorobenzen   Cis-but-2-en   CH3            H C=C H                CH3   TRANS-BUT-2-EN ZAD 2: PROPEN ->PROPAN CH2=CH-CH3 +H2 -> CH3-CH2-CH3 PENTAN -> 1-BROMOPENTAN CH3-CH2-CH2-CH2-CH3 +BR2- > BR-CH2-CH2-CH2-CH2-CH3 BUT-2-YN + 2F2 ->CH3-CF2-CF2-CH3  2,2,3,3-tetrafluorobutan BUT-1-EN+ HCL -> CH3-CCl-CH2-CH3 2-chlorobutan