ile gram NaOH potrzeba do zobojetnienia 12 g kwasu fosforowego (V)?
ile gram NaOH potrzeba do zobojetnienia 12 g kwasu fosforowego (V)?
mNaOH=40u mH3PO4=98u 3NaOH + H3PO4---->Na3PO4 + 3H2O 120g NaOH-------98g H3PO4 xg NaOH----------12g H3PO4 x = 14,7g NaOH
M(NaOH)=23g+16g+1g=40g M(H3PO4)=3*1g+31g+4*16g=98g 3NaOH + H3PO3 -->Na3PO4+3H2O 3*40g---------98g xg-------------12g xg=120g*12g/98g xg=14,7g