Oblicz spałd (% masy) pierwiastków  w kwasie heptanowym .

mC6H13COOH=7*12u+14u+2*16u=130u %C = (84/130)*100% = 64,6% %H = (14/130)*100% = 10,8% %O = (32/130)*100% = 24,6%  

C6H13COOH - kwas heptanowy 7mC=6*12=84g 14mH=14*1=14g 2mO=2*16=32g mC6H13COOH=84g+15g+32g=131g Zawartosc węgla: 7mC/mC6H13COOH * 100% = 84g/131g*100%=64,6% Zawartośc tlenu: 2mO/mC6H13COOH * 100%= 32g/131g * 100%= 24,6% Zawartosc wodoru: 14mH/ mC6H13COOH * 100% = 14g/131g * 100% = 10,8%