a) (x-3)²+3(3x-2)²=x²-6x+9+3(9x²-12x+4)=x²-6x+9+27x²-36x+12=28x²-42x+21 b) (a-3√3) (a+3√3)-(a-1)²=a²-27-a²+2a-1=2a-28 c) (x-3)-(x+3)+(x-3)²=x-3-x-3+x²-6x+9=x²-6x+3 Doprowadź do najprostszej postaci i oblicz: b(a-b)²+2ab-3b²= a=-1, b=1 1(1+1)²+2*1*(-1)-3*1²=4-2-3=-1
(mam nadzieje, że jest dobrze, ale nie jestem pewna.) a) (x - 3)² + 3(3x - 2)² = = (x - 3)(x - 3) + 3(3x - 2)(3x - 2) = = x² - 3x - 3x + 9 + 3(9x² - 6x - 6x + 4) = = x² - 6x + 9 + 27x² - 18x - 18x + 12 = = 28x² - 42x + 21 b) (a - 3√3)(a + 3√3) - (a - 1)² = = a² + 3√3a - 3√3a - 27 - (a - 1)(a - 1) = = a² - 27 - a² - a - a + 1 = = -2a - 26 c) (x - 3) - (x + 3) + (x - 3)² = = x - 3 - x - 3 + (x - 3)(x - 3) = = -6 + x² - 3x - 3x + 9 = = x² - 6x + 3 a=-1, b=1 b(a - b)² + 2ab - 3b² = = b[(a - b)(a - b)] + 2ab - 3b² = = b(a² - ab - ab + b²) + 2ab - 3b² = = a²b - ab² -ab² + b³ + 2ab - 3b² a=-1, b=1 (-1)²*1 - (-1)*1² - (-1)*1² + 1³ + 2*(-1)*1 - 3*1²= =1*1 - (-1)*1 - (-1)*1 + 1 + 2*(-1) - 3*1 = = 1 - (-1) - (-1) + 1 - 2 - 3 = = 1+1+1+1-2-3= =4-2-3= =2-3= -1
