Masa cząsteczkowa: mAl2O3 = 3*16u + 2*27u = 102u mH3PO4 = 4*16u + 3u + 31u = 98u mFe2O3= 2*56u + 3*16g = 160u mMgCl2= 2* 35u + 24u = 94u mCH3COOH= 4u + 2* 12u + 2*16u = 60u Masa molowa: mAl2O3 = 3*16g/mol + 2*27g/mol = 102g/mol mH3PO4 = 4*16g/mol + 3g/mol + 31g/mol = 98g/mol mFe2O3= 2*56g/mol + 3*16g/mol = 160g/mol mMgCl2= 2* 35g/mol + 24g/mol = 94g/mol mCH3COOH= 4g/mol + 2* 12g/mol + 2*16g/mol = 60g/mol Pozdrawiam, kate66 :)
Masa cząsteczkowa..............................Masa molowa mAl2O3=2*27u+3*16u = 102u...................M=102g/mol mH3PO4=3*1u+1*31u+4*16u = 98u.............M=98g/mol mFe2O3=2*56u+3*16u = 160u...................M=160g/mol mMgCl2=24u+2*35,5u = 95u.....................M=95g/mol mCH3COOH=2*12u+4*1u+2*16u = 60u..........M=60g/mol
Oblicz masę cząsteczkową i molową następujących związków chemicznych •Al2O3 •H3PO4 •Fe2O3 •MgCl2 •CH3COOH...
