zad. 7 |AB| = 6cm |AP| + |PB| = |AB| |AM| + |MC| = |AC| |AM| = 3|MC| 3|MC| + |MC| |AC| 4|MC| = |AC| |MC| = 1/4 |AC| |MC| / |AC| = |PB| / |AB| 1/4 |AC| / |AC| = |PB| / |AB| |PB| / |AB| = 1/4 |PB| / 6cm = 1/4 |PB| = 1,5cm |AP| = 6cm - 1,5cm |AP| = 4,5cm zad. 8 a) (2 + 3 + 2) / 6 = (2 + 3) / y 7/6 = 5/y 7y = 30 y = 30/7 (2 + 3 + 2) / 6 = 2 / x 7/6 = 2/x 7x = 12 x = 12/7 P = (x + y)*3/2 P = (12/7 + 30/7)*3/2 P = 6*3/2 P = 18/2 P = 9 b) (3,6 + h) / 2,5 = 3,6 / 1,5 (3,6 + h)*1,5 = 2,5 * 3,6 5,4 + 1,5h = 9 1,5h = 3,6 ||:1,5 h = 2,4 c / 5,5 = 3,6 / (3,6 + 2,4) c / 5,5 = 3,6 / 6 6c = 19,8 ||:6 c = 3,3 P = ((c+1,5) + (5,5+2,5))*h/2 P = (3,3 + 1,5 + 5,5 + 2,5)*2,4/2 P = 12,8*1,2 P = 15,36 c) (3 + 7) / 6 = 7 / a 10a = 42 a = 4,2 H - wys całego trójkąta = 8, bo (3+7), 6 i 8 tworzą trójkę pitagorejską :) h - wys trapezu 3 / (3+7) = h / 8 24 = 10h h = 2,4 P = (a + 6)*h/2 P = (4,2 + 6)*2,4/2 P = 10,2*1,2 P = 12,24
