Napisz równanie reakcji spalania 9 alkanu i 4 alkenu .(3 sposobami)

9 alkan to nonan C9H20 + 14 O2---->9CO2 + 10H2O 2C9H20 + 19 O2---->18CO + 20H2O C9H20 + 5 O2---->9C + 10H2O   4 alken to buten C4H8 + 6 O2---->4CO2 + 4H2O C4H8 + 4 O2---->4CO + 4H2O C4H8 + 2 O2---->4C + 4H2O

nonan: C9H20+14O2----9CO2+10H2O 2C9H20+19O2----18CO+20H2O C9H20+5O2----9C+10H2O   buten: C4H8+6O2----4CO2+4H2O C4H8+4O2----4CO+4H2O C4H8+2O2----4C+4H2O