Prosze o rozwiazanie     zadanie w zalaczniku     zadanie numer 10 rozwiazcie metoda przeciwnych wspolczynnikow

zad.10 a) x/2 + y/3 = 1 1/3 / *6 x/3 - y/2 = 2 1/3 / *6   3x +2y = 8 / *2 2x - 3y = 14 / * (-3)   6x + 4y = 16 -6x + 9y = - 42  + ------------------------   13y = -26 / : 13 y= - 2   3x + 2y = 8 3x + 2 * (-2) = 8 3x = 8 + 4 3x = 12 / : 3 x= 4 y= -2   b) 3/5x + 1/2y = 2 /*10 1/2 (2x-y) =2   6x+5y = 20 x- 1/2y = 2 / * (-6)   6x+5y = 20 -6x +3y = -12 + ---------------------   8y = 8 / : 8 y=1   6x+5y = 20 6x+5*1=20 6x=15/:6 x= 15/6 x=2,5 y=1   c) (x+2)/5-2y=5 |*5 x-(y+2)/6=3 |*6 x+2-10y=25 6x-y-2=18 x-10y=23 6x-y=20 x=23+10y 6(23+10y)-y=20 x=23+10y 138+60y-y=20 x=23+10y 59y=-118 |:59 x=23+10y y=-2 x=23+(-2*10)=23-20=3 d) (x+y)/2-x/3=4 |*6 (x-y)/2+y/3=-3 |*6 3x+3y-2x=24 3x-3y+2y=-18 x+3y=24 3x-y=-18 x=24-3y 3(24-3y)-y=-18 x=24-3y 72-9y=-18 x=24-3y 9y=90 |:9 x=24-3y y=10 x=24-30=-6 e) (3x-1)/5+(2y-3)/4=(3y+3)/2 |*20 (x+y)/4-(3y-1)/2=(x-6y)/4 *4 12x-4+10y-15=30y+30 x+y-(6y-2)=x-6y 12x+10y-19=30y+30 x+y-6y+2=x-6y 12x+10y-30y=49 x-5y-x+6y=-2 12x-20y=49 y=-2 12x=49+20y y=-2 12x=49-40=9 x=0,75 f) (3x-2)/3-(2x+y)/6=x+1/6 |*6 x+y-(-x+y)/5=1/5-0,8x |*5 6x-4-2x-y=6x+1 5x+5y+x-y=1-4x 4x-4-y=6x+1 6x+4y=1-4x -2x-y=5 10x+4y=1 y=-2x-5 10x+4(-2x-5)=1 y=-2x-5 10x-8x-20=1 y=-2x-5 2x=21 |:2 y=-2x-5 x=10,5 y=-21-5=-26