Rozwiąż równania: x3-2x2-x+2=0 x3+3x2+x+3=0 x3+x2-2x-2=0 x+2/x-1 =2     x – 2/ 2x+4 = 2/x-2     Bardzo proszę o szybkie rozwiązanie

    a)x³-2x²-x+2=0 x²(x-2)-1(x-2)=0 (x²-1)(x-2)=0 (x-1)(x+1)(x-2)=0 x=1, x=-1, x=2   b)x³+3x²+x+3=0 x²(x+3)+1(x+3)=0 (x²+1)(x+3)=0 x∈R  x=-3   c)x³+x²-2x-2=0 x²(x+1)-2(x+1)=0 (x²-2)(x+1)=0 (x-√2)(x+√2)(x+1)=0 x=√2, x=-√2, x=-1   d) x+2/x-1 =2 2(x-1)=x+2 2x-2=x+2 2x-x=2+2 x=4   e) x – 2/ 2x+4 = 2/x-2 (x-2)²=2(2x+4) x²-4x+4=4x+8 x²-4x-4x=8-4 x²-8x=4 x²-8x-4=0 Δ=80 √Δ=4√5 x₁=(8-4√5):2 x₁=4-2√5 x₂=4+2√5